Valentine's Day Maze: |
On each move, one of your pointers travels over a colored path to an adjacent circle. Either pointer can move; there is no need to alternate pointers. And there is this restriction: the color of the path a pointer travels on must match the color of the circle that the other pointer is on. Answer, page 00 |
Solution to the Valentine's Day maze: There are quite a few different paths to the goal, but the following is the shortest. It shows the different states you have to go through. The starting state is AB, meaning one pointer is on circle A and the other is on circle B. The next state you go to is AC, meaning one pointer's on A and the other is on B. You continue until you reach the final state BB, which means both pointers are on B. AB-AC-BC-BD-CD-CE-CL-BL-BF-BG-CG-CH-DH-DJ-CJ-CK-BK-BB If you liked this maze, you might be interested in the complete state diagram of it. When Robert Abbott created the maze, he found it was hard to see where every path was going, and he wanted to make sure there weren't any very short paths to the goal. So he drew the state diagram shown below. In addition to helping in the construction of the maze, it's sort of fun to travel around this diagram as you travel around the maze. In the diagram, the shortest solution is shown in red. |
"Meteor Storm!" was horribly complex, and I'm pretty sure no one solved it. Most of the mazes in Mad Mazes were too hard. When I wrote the book I thought I should make the mazes as hard as I could. That was obviously a bad idea, but at the time I didn't even think of it. I wish someone had told me. Note, February 6, 2009: The page you are reading was part of a memo I wrote to GAMES magazine. It contained five mazes that I thought would make good covers for GAMES. They did accept the Valentine's Day maze, but they came up with a much better theme and called it Charge. Here's what it looked like: |
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